A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of `CO_(2)`. The empirical formula of the hydrocarbon is:

Options

A. `C_7H_8`
B. `C_2H_4`
C. `C_3H_4`
D. `C_6H_5`

Answer

A

Explanation

Let the mass of gaseous hydrocarbon taken=w gm
`:. % C = 12/44xx(3.08)/wxx100= 84/w , " " % H=2/18xx(0.72)/(w) xx100=8/w`
Rate of C : H atoms `84/wxx1/12 : 8/wxx1/1 = 7.8" "` Thus .E.F. `=C_7H_8`