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A compound contains 38.8%C, 16%H, and 45...

A compound contains 38.8%C, 16%H, and 45.2%N. The formula of the compound would be:

A

`CH_3NH_2`

B

`C_2H_5CN`

C

`CH_3CN`

D

`CH_2(NH_2)_2`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(C,:,H,:,N),((38.8)/12,:,16/1,:,(45.2)/14),(3.23,:,16,:,3.2),(1,:,5,:,1):}`
MF = `CH_5N = CH_3 NH_2`
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