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0.14 gm of an acid required 12.5 ml of 0...

0.14 gm of an acid required 12.5 ml of 0.1 N NaOH for complete neutralisation. The equivalent mass of the acid is:

A

63

B

56

C

45

D

112

Text Solution

Verified by Experts

The correct Answer is:
D
mEq. of NaOH = `12.5 xx0.1 = 1.25`
mEq. of acid = mEq. of NaOH
Equivalent =* `(Wt)/(Ew) " " :. Ew = (Wt)/("Equivalent") = (0.14)/(1.25xx10^(-3))=112`
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