500 mL of a hydrocarbon gas burtn in excess of oxygen yielded 2500 mL of `CO_(2)` and 3.0 litre of water vapour (all volumes measured at the same temperature and pressure). The formula of the hydrocarbon is:

Options

A. `C_3H_6`
B. `C_2H_4`
C. `C_5H_(12)`
D. `CH_4`

Answer

C

Explanation

`C_xH_y+[x+y/4]O_2 rarrxCO_2+y/2H_2O(v)`
`{:(500,0,0),(0,500x ,y/2xx500):}`
Now, `500x = 2500 " " :. X = 5 , " " 500(y)/2 = 3000 :. Y = 12 :. "Alkane is" C_5H_(12)`