1.575 g of an organic acid was dissolved...

1.575 g of an organic acid was dissolved in 250 mL of water. 20 mL of this solution required 16 mL of N/8 alkali solution for complete neutralisation. If the basicity of the acid is two, find its molecular mass.

182

136

126

148

Text Solution

Verified by Experts

The correct Answer is:

16 mL N/8 alkali solution = 20 mL of acid solution
2mL 1 N alkali solution = 20 mL of acid solution
`(2xx 250 )/(20) mL` 1 Nalkali solution = 250 mL of acid solution.
25 mL I Nalkali solution = 1.575 g acid
1000 mL 1 N alkali solution `= (1.575)/25xx1000` g acid
Eq. mass of the acid=63 g acid, Molecular mass of the acid `=63 xx2=126 `

Topper's Solved these Questions

PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS
BRILLIANT PUBLICATION|Exercise LEVEL- III (Single Correct Answer Type)|7 Videos
PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS
BRILLIANT PUBLICATION|Exercise LEVEL- III (Multiple Correct Answer Type)|9 Videos
PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS
BRILLIANT PUBLICATION|Exercise LEVEL- III (Linked Comprehension Tyne (Paragraph I))|12 Videos
p-BLOCK ELEMENTS
BRILLIANT PUBLICATION|Exercise LEVEL- III (Linked Comprehension Type) (Paragraph IV )|3 Videos
REDOX REACTIONS
BRILLIANT PUBLICATION|Exercise LEVEL -III|50 Videos

Similar Questions

Explore conceptually related problems

A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. Ammonia evolved was absorbed in 50 mL of 0.5 M H_2SO_4 . The residual acid required 60 mL or 0.5 M NaOH solution for neutralisation. Find the percentage composition of nitrogen in the compound.

1.0 g of a weak monobasic acid HA in 100 g water lowers the freezing point by 0.155 K. If 0.45 g, of same acid requires 15 mL of N/5 NaOH solution for complete neutralistion then %, degree ofionization of acid is (K_f " of H"_(2)O="1.86 K kg mol"^(-1)) . a)0.2 b)0.25 c)0.4 d)0.5

BRILLIANT PUBLICATION-PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS-LEVEL- II

A compound contains 38.8%C, 16%H, and 45.2%N. The formula of the compo...
Text Solution
|
An organic compound on analysis gave C = 42.8%, H = 7.2%, and N = 50%....
Text Solution
|
0.14 gm of an acid required 12.5 ml of 0.1 N NaOH for complete neutral...
Text Solution
|
0.24 gm of a volatile liquid upon vaporisation gives 45 ml of vapours ...
Text Solution
|
Liquid benzene (C(6)H(6)) burns in oxygen according to 2C(6)H(6)(l)+15...
Text Solution
|
Some organic compounds are purified by distillation at low pressure be...
Text Solution
|
Which is useful for separating benzoic acid from a mixture of benzoic ...
Text Solution
|
500 mL of a hydrocarbon gas burtn in excess of oxygen yielded 2500 mL ...
Text Solution
|
Which compound present in sodium extract prepared using thio urea, giv...
Text Solution
|
The sodium extract on acidification with acetic acid and then adding l...
Text Solution
|
An organic compound is fused with fusion mixture and extracted with HN...
Text Solution
|
Which one of the following hydrocarbons is burnt in excess of oxygen, ...
Text Solution
|
Sodium nitroprusside reacts with sulphide ion to give a purple colour ...
Text Solution
|
1.575 g of an organic acid was dissolved in 250 mL of water. 20 mL of ...
Text Solution
|
In the Kjeldahl's method for estimation of nitrogen in a soil sample, ...
Text Solution
|
0.0833 mole of a carbohydrate of empirical formula CH(2)O contains 1.0...
Text Solution
|
Analysis of an organic compound gave 74% C, 8.65% H and 17.3% N. What ...
Text Solution
|
0.16 g of a dibasic organic acid required 25cm^(3) of 0.1 M NaOH for c...
Text Solution
|
9.9 g amide with molecular formula C(4)H(5)N(x)O(y) on heating with al...
Text Solution
|
In a compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. M...
Text Solution
|