0.0833 mole of a carbohydrate of empiric...

0.0833 mole of a carbohydrate of empirical formula `CH_(2)O` contains 1.00 g of hydrogen. The molecular formula of the carbohydrate is:

`C_5H_10O_5`

`C_3H_4O_3`

`C_(12)H_(22)O_11`

`C_6H_(12)O_6`

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The correct Answer is:

1 mole of carbohydrate will contain `1/(0.8278)` of hydrogen, ie, 12 g hydrogen.
`:.` The molecular formula of the compound will be `C_2H_(12)O_6`.

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