Analysis of an organic compound gave 74%...

Analysis of an organic compound gave 74% C, 8.65% H and 17.3% N. What is the empirical formula of the compound.

`C_5H_8N`

`C_(10)H_(12)N`

`C_5H_7N`

`C_(10)H_(14)N`

Text Solution

Verified by Experts

The correct Answer is:

`:.` Empirical formula of the compound= `C_5H_7N `

Topper's Solved these Questions

PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS
BRILLIANT PUBLICATION|Exercise LEVEL- III (Single Correct Answer Type)|7 Videos
PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS
BRILLIANT PUBLICATION|Exercise LEVEL- III (Multiple Correct Answer Type)|9 Videos
PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS
BRILLIANT PUBLICATION|Exercise LEVEL- III (Linked Comprehension Tyne (Paragraph I))|12 Videos
p-BLOCK ELEMENTS
BRILLIANT PUBLICATION|Exercise LEVEL- III (Linked Comprehension Type) (Paragraph IV )|3 Videos
REDOX REACTIONS
BRILLIANT PUBLICATION|Exercise LEVEL -III|50 Videos

Similar Questions

Explore conceptually related problems

The percentage composition of a compound is C = 10%, Cl= 89.2%, H = 0.84%. Empirical formula of the compound is

The molecular mass of an organic compound is 78 and its composition is 92.4% C and 7.6% H. Determine the molecular formula of the compound.

0.200 g of an organic compound gave 0.235 g AgI by Carius method. Percentage of iodine in the compound is

2g of an organic compound gave 1.88 g AgBr in Carius method. Percentage of bromine in the compound is

The chemical compounds are represented by both empirical and Molecular formula. A very popular organic compound is a major constituent of alcoholic drinks. What is the molecular formula of the compound?

0.32 g of an organic compound gave 0.932 g BaSO_4 in Carius method. Percentage of sulphur in the compound is

BRILLIANT PUBLICATION-PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS-LEVEL- II

A compound contains 38.8%C, 16%H, and 45.2%N. The formula of the compo...
Text Solution
|
An organic compound on analysis gave C = 42.8%, H = 7.2%, and N = 50%....
Text Solution
|
0.14 gm of an acid required 12.5 ml of 0.1 N NaOH for complete neutral...
Text Solution
|
0.24 gm of a volatile liquid upon vaporisation gives 45 ml of vapours ...
Text Solution
|
Liquid benzene (C(6)H(6)) burns in oxygen according to 2C(6)H(6)(l)+15...
Text Solution
|
Some organic compounds are purified by distillation at low pressure be...
Text Solution
|
Which is useful for separating benzoic acid from a mixture of benzoic ...
Text Solution
|
500 mL of a hydrocarbon gas burtn in excess of oxygen yielded 2500 mL ...
Text Solution
|
Which compound present in sodium extract prepared using thio urea, giv...
Text Solution
|
The sodium extract on acidification with acetic acid and then adding l...
Text Solution
|
An organic compound is fused with fusion mixture and extracted with HN...
Text Solution
|
Which one of the following hydrocarbons is burnt in excess of oxygen, ...
Text Solution
|
Sodium nitroprusside reacts with sulphide ion to give a purple colour ...
Text Solution
|
1.575 g of an organic acid was dissolved in 250 mL of water. 20 mL of ...
Text Solution
|
In the Kjeldahl's method for estimation of nitrogen in a soil sample, ...
Text Solution
|
0.0833 mole of a carbohydrate of empirical formula CH(2)O contains 1.0...
Text Solution
|
Analysis of an organic compound gave 74% C, 8.65% H and 17.3% N. What ...
Text Solution
|
0.16 g of a dibasic organic acid required 25cm^(3) of 0.1 M NaOH for c...
Text Solution
|
9.9 g amide with molecular formula C(4)H(5)N(x)O(y) on heating with al...
Text Solution
|
In a compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. M...
Text Solution
|