9.9 g amide with molecular formula `C_(4)H_(5)N_(x)O_(y)` on heating with alkali liberated 1.7 g of ammonia. If the percentage of oxygen is 33.33% then the ratio of 'N' and 'O atoms in the compound is:

Options

A. `1:1`
B. `1:2`
C. `2:3`
D. `3:2`

Answer

B

Explanation

Amide `C_4H_5 N_xO_y` will given x mole `NH_3 :.` Molecular mass of amide `= (9.9)/(1.7) xx17 x = 99x`
`%` Nitrogen in the amide `= (14x)/(99x) xx100 = 14.14 , ` % Oxygen in the amide = 33.33
Ratio of number of atom of .N. and .O. = `(14.14)/(14) : (33.33)/16 =1:2`