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0.4 gm of an organic compound was treate...

0.4 gm of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 ml of `0.5 MH_3PO_3`. The residual acid required 30 ml of 0.5 M `Ca(OH)_2` Find the percentage of `N_2` in the compound. (answer is divided by 10)

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The correct Answer is:
7

Here `H_3 PO_3 ` is diabasic (ie ,n = 2)
The normality of `H_3PO_3 = M xx n = 0.5 xx2 =1N`
mEq. Of `H_3PO_3 = 50xx0.5 xx2 =50`
mEq. Of `Ca(OH)_2 =30 xx0.5 xx2=30`
Excess of acid used to neutralise `NH_3 = 50 -30=20 `
Percentage of `N_2 = (1.4 xx "mEq.of acid used to neutralise" NH_3)/("Weight of compound ") = (1.4 xx20)/(0.4) =70%`
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