0.76 gm of the silver salt of a dibasic acid was ignited. It gave 0.54 gm of pure silver. Determine the molecular mass of the acid.

Answer

9

Explanation

Mass of the silver salt taken=0.76 gm
Mass of the silver left = 0.54 gm
Basicity of the acid = 2
Equivalent mass of acid (E)
`("Weight of silver salt")/("Equivalent weight of silver salt") = ("Weight of the silver")/("Equivalent weight of silver")` we get `(0.76)/(E+107)=(0.54)/(108)`
Thus, the equivalent weight of acid (E) = 45.
Mw=Ew `xx` bạsicity `=45 xx 2 =90.` Thus the molecular mass of the dibasic acid is 90.