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An acid of molecular mass 104 contains 3...

An acid of molecular mass 104 contains 34.6% carbon and 3.85% hydrogen. 3.812 mg of the acid required 7.33 ml of 0.01 N NaOH for neutralisation. Calculate the basicity of the acid.

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The correct Answer is:
2
mEq. of NaOH = `7.33 xx0.01 = 0.0733` mEq. of acid = 0.0733
Equivalent of acid = `("Weight")/(Ew)` , Ew of acid `("Weight")/("Equivalent of acid") (3812xx10^(-3)gm)/(0.0733 xx 10^(-3) ) ~~52 gm`
`:. ` Basicity (n) `= ("Molecular mass")/("Equivalent ") = (104)/52 =2`
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