Addition of HBr on `CH-=C-CH_2-CH=CH_2` and `CH-=C-CH=CH_2` separately gives :

Options

A. `CH-=C-CH_(2)-CHBr-CH_(3)andCH_(2)=underset(Br)underset(|)(C)-CH=CH_(2)`
B. `CH=underset(Br)underset(|)(C)-CH_(2)-CHBr-CH_(2)andCH_(2)=underset(Br)underset(|)(C)-CH=CH_(2)`
C. `CH-=C-CH_(2)-underset(Br)underset(|)(CH)-CH_(3)andCH_(2)-=C-underset(Br)underset(|)(C)H=CH_(3)`
D. None of these

Answer

A

Explanation

The first addition will occur on double bond. Thus,
`CH-=C-CH_(2)-CH=CH_(2)overset(HBr)toCH-=C-CH_(2)-CHBr-CH_(3)` but in `CH-=C-CH=CH_(2)`, the addtion will occur at `CH-=C-` because the product formed is conjugated alkadiene, which is more stable.
`CH-=C-CH=CH_(2)overset(HBr)toCH_(2)=underset(Br)underset(|)(C)-CH=CH_(2)`