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An alkyne having molecular mass x xx 10 ...

An alkyne having molecular mass x `xx` 10 (A) is treated with Lindlar's catalyst and `H_(2)` to give a compound (B). (B) reacts with HCl to give a compound ( C). When ( C) reacts with metallic sodium in presence of ether it gives (D). The molecular mass of (D) is 86. What is the value of x?

Text Solution

Verified by Experts

The correct Answer is:
4

Calculated mass of (D) = `2(10xxx+2+36.5)-2xx36.5+2=20x+6`
[After Wurtz reaction, deduct two chlorine atoms and add two hydrogen atoms.]
Therefore, Mol. of mass calculated = Molecular mass given 20x + 6 = 86
`x=(86-6)/20=4" "therefore` the alkyne is propyne with molecular mass 40.
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