At what temperature will the volume of a gas at `27^(@)C` doubles itself at constant pressure?

Explanation

Given `V_(1) = V L , T_(1) = (273 + 27) = 300 K , V_(2) = 2 V L , T_(2) = `?
According to Charles law , `(V_(1))/(T_(1)) = (V_(2))/(T_(2)) implies T_(2) = (V_(2) xx T_(1))/(V_(1)) = (2 V L xx 300 K)/(VL) = 600 K (327^(@) C)`