A sample of gas occupies volume of `750 cm^(3)` at `27^(@)C`. Calculate the temperature at which it will occupy a volume of `350 cm^(3)?`

Explanation

Given , `V_(1) = 750 cm^(3) , T_(1) = (273 + 27) =300 K , V_(2) = 350 cm^(3) , T_(2)` = ?
By Charles law , `(V_(1))/(T_(1)) = (V_(2))/(T_(2)) implies T_(2) = (V_(2) xx T_(1))/(V_(1)) = (350 cm^(3) xx 300 K)/(750 cm^(3)) = 140 K (133^(@) C)`