`5.0g` of oxygen is introduced into an evacuated vessel of `10 dm^3` capacity maintained at `25^(@)C`. Calculate the pressure of the gas in the container assuming that the gas behaves ideally.

Explanation

Given , `V = 10 dm^(3) , T = 25 + 273 = 298 K , R = 0.0821 dm^(3)` atm `K^(-1) mol^(-1)` ,
n = w/M = 5g/32 g `mol^(-1) = 0.156 mol^(-1)`
Pressure of gas , `P = (n RT)/(V) = (0.156 mol xx 0.0821 dm^(3) "atm" K^(-1) mol^(-1) xx 298 K)/(10 dm^(3)) = 0.382` atm