Calculate the average translation kinetic energy of an ideal gas per molecule `(epsilon)` and per mole (E ) at `25^(@)C`. (Boltzmann constant, `k= 1.38 xx 10^(-23)JK^(-1)`).

Explanation

`epsilon = (3)/(2) kT = 3//2 (1.38 xx 10^(-23)J K^(-1)) (298 K) = 6.17 xx 10^(-21) J "molecule"^(-1)`
`E = (3)/(2) RT = 3//2 ( 8.314 J K^(-1) mol^(-1)) (298 K) = 3.716 xx 10^(3) J mol^(-1)`