Calculate the critical temperature of a van der Waals gas for which `P_c` is 73 atm and b is `34cm^(3) mol^(-1)`.

Explanation

van der Waals constant , a `= P_(c) 27 b^(2)`
Critical temperature ,
`T_(c) = (8a)/(27 Rb) = ((8) (P_(c) 27 b^(2)))/(27 Rb) = (8P_(c) b)/( R) = ((8) (73 "atm") (0.034 dm^(3) mol^(-1)))/(0.08206 dm^(3) "atm" K^(-1) mol^(-1)) = 41.97` K