The vapour pressure of water at `80^(@)C" is "355 mm Hg`. A one-litre vessel contains `O_(2)" at "80^(@)C`, saturated with water vapour the total pressure being 760 mm Hg. The contents of the vessel were pumped into `0.3L` vessel at the same temperature. What is the partial pressure of `O_(2)`?

Options

A. 1350 mm Hg
B. 2263.3 mm Hg
C. 123.5 mm Hg
D. 455 mm Hg

Answer

A

Explanation

Given that `P_(H_(2) O) = 355` mm Hg at `80^(@) C , P_(O_(2))= 405` mm Hg
According to Boyle.s law , `p_(1) V_(1) = p_(2 ) V_(2)` . Substituting values , we get `p_(1) = (405 xx 1)/(0.3) = 1350` mm Hg