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1 mol" of "N(2) gas at 0.8 atm takes 38s...

`1 mol" of "N_(2)` gas at `0.8 atm` takes 38s to diffuse through a pinhole, whereas 1 mol of an unknown gas at `1.6 atm` takes 57s to diffuse through the same pinhole. The molecular weight of unknown gas is

A

126

B

64

C

80

D

252

Text Solution

Verified by Experts

The correct Answer is:
D

`(n_(1))/(t_(1)) xx (t_(2))/(n_(2)) = (p_(1))/(p_(2)) xx sqrt((M_(2))/(M_(1))) implies (1)/(38)xx (57)/(1)= (0.8)/(1.6) sqrt((M_(2))/(28)) implies M_(2) = 252`
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