Rate of diffusion of LPG (a mixture of n-butane and propane) is 1.25 times that of `SO_(3)` Hence, mole fraction of n-butane in LPG is

Options

A. 0.752
B. 0.256
C. 0.514
D. 0.667

Answer

C

Explanation

Since `(r_(SO_(2)))/(r_("mix")) = sqrt((M_("mix"))/(M_(SO_(3)))) implies (1)/(1.25) = sqrt((M_("mix"))/(80)) implies M_("mix") = 51.2`
Since `, M_("mix") = X_("butane") + X_("propane") ` , Therefore , 51.2 = `58 x_("butane") + 44 (1- x_("butane"))`
`implies 7.2 = 14 xx x_("butane") implies X_("butane") = 0.514`