At STP, a container has 1 mole of He, 2 mole Ne, 3 mole `O_(2)` and 4 mole `N_(2)`. Without changing total pressure if 2 mole of `O_(2)` is removed, the partial pressure of `O_(2)` will be decreased by:

Options

A. 0.26
B. 0.4
C. 0.5833
D. 0.6666

Answer

C

Explanation

`P_(O_(2)) = (3)/(10) xx P_(T) ,` After removing 2 mole of `O_(2) implies P_(O_(2)) = (1)/(8) xx P_(T)`
Decreasing in p.pr. , of `O_(2) = ((3P_(T))/(10) - (P_(T))/(8))/((3P_(T))/(10)) xx 100 = 58.33`