Two closed vessels of equal volume containing air at pressure `p_1` and temperature `T_1` are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at `T_1` and that in the other at `T_2`, what will be the pressure in the vessels?

Options

A. `(2p_(1)T_(1))/(T_(1) + T_(2))`
B. `(T_(1))/(2p_(1) T_(2))`
C. `(2p_(1) T_(2))/(T_(1) + T_(2))`
D. `(2p_(1))/(T_(1) + T_(2))`

Answer

C

Explanation

Volume of the system and amount of gas remains constant . Applying Charle.s law ,
`(p_(1))/(T_(1)) + (p_(1))/(T_(1)) = (p)/(T_(1)) + (p)/(T_(2)) implies (2p_(1))/(T_(1)) = p ((T_(1) + T_(2))/(T_(1) T_(2))) or p = (2p T_(2))/(T_(1) + T_(2))`