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A 15.0 L cylinder of Ar gas is connected...

A `15.0 L` cylinder of Ar gas is connected to an evacuated `235.0 L` tank. If the final pressure is 750 mm Hg, what have been the original gas pressure in the cylinder? : `76 atm`, `12.56 atm`, `16.45 atm`, `23 atm`

A

76 atm

B

12.56 atm

C

16.45 atm

D

23 atm

Text Solution

Verified by Experts

The correct Answer is:
C
From Boyle.s law `p_(1) V_(1) = p_(2) V_(2)`
`p_(1) = (p_(2) V_(2))/(V_(1)) = (750 xx 250)/(15) [V = 235 + 15 = 250 L] = 12500` mm Hg = 16.45 atm
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