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For the reaction 2NH(3) (g) to N(2) (g)+...

For the reaction `2NH_(3) (g) to N_(2) (g)+ 3H_(2) (g)`. What is the `%` of `NH_(3)` converted if the mixture diffuses twice as fast as that of `S_(2)` under similar conditions?

A

`3.125`

B

`6.25`

C

`12.5`

D

`9.25`

Text Solution

Verified by Experts

The correct Answer is:
B
Moles of `NH_(3)` taken = 1 = 17 g , degree of dissociation = `alpha`
Moles of mixture formed = `1 + alpha` , average molar mass = `(17)/(1 + alpha) = 16 implies alpha = (1)/(16) = 6.25%`
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