The average speed at temperature `T^(@)C` of `CH_(4)(g)` is `sqrt((28)/(88)) xx 10^(3) ms^(-1)`. What is the value of T?

Options

A. `240.55^(@) C`
B. `-32.45^(@) C`
C. `3000^(@) C`
D. `-24.055^(@)C`

Answer

B

Explanation

`sqrt((8RT)/(pi M)) = sqrt((28)/(88)) = sqrt((7)/(22)) = (8 xx 8.314 xx T)/(pi xx 16 xx 10^(-3)) = (7)/(22) xx 10^(6)`
`T = (1000 xx 2)/(8.314) = 240.55 K , T^(@) C = 240.55 - 273 = -32.45^(@) C`