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A gaseous mixture containing He, CH(4)" ...

A gaseous mixture containing `He, CH_(4)" and "SO_(2)` was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially? If mixture contain `He, CH_(4)" and "SO_(2)` in 1 : 2 : 3 mole ratio

A

`2 : 2 : 3`

B

`6 : 6: 1`

C

`sqrt2 : sqrt2 : 3`

D

`4 : 4 :3 `

Text Solution

Verified by Experts

The correct Answer is:
D
`(n._(He))/(n._(CH_4)) = (1)/(2) sqrt((16)/(4)) = (1)/(1) , (n._(He))/(n._(CO_2)) = (1)/(3) sqrt((64)/(4)) = (4)/(3) , n._(He) : n._(CH_(4)) : n ._(SO_2) = 4 : 4 : 3`
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