The compressibility factor for nitrogen at 330 K and 800 atm is `1.90` and at 570 K and 200 atm is `1.10`. A certain mass of `N_2` occupies a volume of `1 dm^(3)` at 330 K and 800 atm. Calculate volume occupied by same quantity of `N_(2)` gas at 570 K and 200 atm.

Options

A. 1 L
B. 2 L
C. 3 L
D. 4 L

Answer

D

Explanation

`Z = (PV)/(nRT) , 1.90 = (1 xx 800)/(n xx R xx 330) , n = (1 xx 800)/(1.90 xx R xx 330) , Z = 1.10 = (V xx 200)/(n xx R xx 570)`
`1.10 = (V xx 200 xx 1.90 xx R xx 330)/(800 xx R xx 570) V = 4 L`