At `100^(@)C` and 1 atm, if the density of liquid water is 1.0 g `cm^(-3)` and that, of water vapour 0.0006 g `cm^(-3)` then the volume occupied by water' molecules in 1 litre of steam at that temperature is

Options

A. `6 cm^(-3)`
B. `60 cm^(3)`
C. `0.6 cm^(3)`
D. `0.06 cm^(3)`

Answer

C

Explanation

Mass of 1000 mL steam = `1000 xx 0.0006 = 0.6 g therefore` Volume of liquid water = `(0.6)/(1) = 0.6 cm^(3)`