The diffusion coefficient of an ideal gas is proportional to its mean free path and mean speed. The absolute temperature of an ideal gas is increased 4 times and its pressure is increased 2 times. As a result, the diffusio coefficient of this gas increases x times. The value of x is

Answer

4

Explanation

Diffusion coefficient , `D = (1)/(2) lambda xx v_(av) implies lambda = - (RT)/(sqrt2 pi sigma^(2) N_(A) P) , v_(av) = sqrt((8RT)/(pi M))`
`D prop (T^(1//2))/(P) implies (D_(2))/(D_(1)) = ((T_(2))/(T_(1)))^(3//2) xx (P_(1))/(P_(2)) = (8)/(2) = 4`