The following data is known about the melting of `KCl`, `Delta H =7.25 kJ mol ^(-1)`, and `Delta S = 0.007 kJ K ^(-1) mol ^(-1).` Calculate its melting point.

Explanation

`Delta S _("fusion")= ( Delta H _("fusion"))/( T _(f)) or T _(f) = ( Delta H _(fus))/( Delta S _(fus)) = ( 7.25 kJ mol ^(-1))/( 0. 007 kJ K ^(-1) mol ^(-1)) = 1035. 7 K`