At one atmosphere pressure, ether boils at `35.5^(@)C.` at what temperature will it boil at a pressure of 750 mm Hg, given that heat of vaporisation of ether is 369 `Jmol^(-1)`.

Explanation

`(ln 750 mm)/(76 mm) = (369.86 J g ^(-1) xx74 g mol ^(-1))/( 8. 314 J K ^(-1) mol ^(-1)) (( T _(2) - 306.5 K)/(306.5 K ))`
`T _(2) = 305. 9 k`
`implies k = 2 b ar m ^(-1) implies ( p _(2) )/( p _(1)) = (d _(2))/(d _(1)) implies d_(2) = d _(1) (( p _(2))/( p _(1))) = 0. 5 xx 5 = 2. 5 m`
Also, `-dW = p dV, V = (4)/(3) pi ((d)/(2)) ^(3) = (4)/(3) pi (d ^(3))/( 8) = (pi)/(6) d ^(3)`
`implies dV = (pi)/(6) 3d ^(2)d d = (pi)/(2) d ^(2) d d implies - dW = kd xx (pi)/(2) d ^(2) d d = (k)/(2) pi d ^(3) d d `
`implies - W = int -dW = (k)/(2) pi int _( d _(1)) ^( d _(2))d ^(3) dd = (k pi)/( 2) [ (d ^(2))/( 4) ] _( d _(1)) ^(d _(2)) = (kpi )/( 8) (d _(2) ^(4) - d _(1) ^(4))`