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One mole of ethanol is treated with one ...

One mole of ethanol is treated with one mole of ethanoic acid at `25^(@)C`. Half of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be

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The correct Answer is:
1
`{:(,C_(2)H_(5)OH+,CH_(3)COOH,hArr,CH_(3)COOC_(2)H_(5)+,H_(2)O),("Initial",1,1,,0,0),("At equ.",1-(1)/(2),1-(1)/(2),,(1)/(2),(1)/(2)):}`
`K = ([CH_(3)COOC_(2)H_(5)][H_(2)O])/([C_(2)H_(5)OH][CH_(3)COOH]) = ((1)/(2) xx (1)/(2))/((1)/(2) xx (1)/(2)) =1`
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