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The mass defect for ""(17)^(35)Clis foun...

The mass defect for `""_(17)^(35)Cl`is found to be 0.32 amn. Calculate the binding energy per nucleon.

A

7.31 MeV

B

9.31 MeV

C

8.516 MeV

D

4.34 MeV

Text Solution

Verified by Experts

The correct Answer is:
C
Binding Energy (BE) = `Deltam xx 931.48` Mev = 0.32 amu ` xx 931.48 = 298.07` Mev
`(B.E)/("nucleon") = ("Total BE")/("No. of nucleons") = (298.07)/(35) = 8.516` Mev
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