One of the most stable nuclei is `""^(55)`. Mn. Its nuclide mass is 54.938 amu. Determine binding energy per nucleon (mass of proton: 1.00783u and neutron :1.00867 u).

Options

A. 6.18 Mev/nucleon
B. 7.18 Mev/nucleon
C. 8.76 Mev/nucleon
D. 5.26 Mev/nucleon

Answer

C

Explanation

Mass of `""^(55)Mn = (25 xx m_(p)) + (30 + m_(n)) = (25 xx 1.00783) + (30 xx 1.00867)`
`= 25.19575 + 30.26010 = 55.45585` amu
Mass defect `Deltam = 55.938 - 55.45585 = 0.48215` amu
B.E. per nucleon ` = (0.48215 xx 931.48)/(55) = 8.16` Mev/nucleon