Energy for the combustion of 1 mole ethylene in oxygen is `-1.4 xx 10^(3)` KJ. What would be the loss in mass (expressed in amu) accompanying the oxidation of one molecule of ethylene ?

Options

A. `1.2 xx 10^(-8)` amu/molecule
B. `1.6 xx 10^(-6)` amu/molecule
C. `1.4 xx 10^(-8)` amu/molecule
D. `1.6 xx 10^(-8)` amu/molecule

Answer

D

Explanation

`Deltam = (DeltaE)/(C^(2)) = (-1.4 xx 10^(3) xx 10^(3) xx 10^(3))/((3 xx 10^(8))^(2)) = 1.6 xx 10^(-8)` amu/molecule