Calculate the energy released in the formation of argon atom `""_(18)^(40`)Ar. Isotopic mass of Ar = 39.962384 amu (mass of proton : 1.00 783u and neutron: 1.00867 u).

Answer

C

Explanation

Packing fraction (p) `= (m-A)/(A) xx 10^(4) = (39.962384)/(40) xx 10^(4) = 9.404`
Mass defect ` = 22 xx m_(n) + 18 xx m_(p) + 18m_(e) - A = 40.3314 - 39.962384 = 0.36916` amu
B.E.` = Deltam xx 931.48` Mev ` =0.369016 xx 931.48 = 343.73` Mev