One mole of fuel on combustion liberates 1800 KJ of energy. Calculate the loss in mass during the combustion.

Options

A. `5 xx 10^(-11)` kg
B. ` 2 xx 10^(-11)` kg
C. `2 xx 10^(-9)` kg
D. `2 xx 10^(-12)`kg

Answer

B

Explanation

`DeltaH = DeltaH xx e^(2) therefore Deltam = (DeltaH)/(c^(2)) = (1800 xx 10^(3))/((3 xx 10^(8))^(2)) = 2 xx 10^(-11)` kg