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Boron has two isotopes ""(5)^(10)B and "...

Boron has two isotopes `""_(5)^(10)B` and `""_(5)^(11)B`. If the atomic weight of boron is 10.81, the ratio of `""_(5)^(10)B` and `""(5)^(11)B` in nature is

A

`(19)/(81)`

B

`(20)/(53)`

C

`(15)/(16)`

D

`(10)/(11)`

Text Solution

Verified by Experts

The correct Answer is:
A
Let .x. and `(1-x)` be the amount of `""_(5)^(10)B`. Then
`10x + 11 (1-x) = 10.81, " "10 x-11x = 10.81 - 11.00 " "therefore x =0.19`
`1 -x = 1-0.19 = 0.81 " "therefore` Ratio of `""_(5)^(10)B, ""_(5)^(11)B = 19:81`
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