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The energy released in the fission react...

The energy released in the fission reaction `""U^(236) to ""X^(117) + Y^(117) + 2 ""_(0)n^(1)`, given that the binding energy per nucleon of X and Y is 8.5 MeV and that of `""_(92)U^(236)` is 7.6 MeV, is nearly.

A

220 MeV

B

180 MeV

C

195 meV

D

190 MeV

Text Solution

Verified by Experts

The correct Answer is:
C
Energy released is given by, `E = 117 xx 8.5 + 117 xx 8.5 - 236 xx 7.6 = 1989 - 1794 = 195` MeV
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