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In an old rock, the mass ratio of ""(92)...

In an old rock, the mass ratio of `""_(92)^(238)U to ""_(82)^(206)Pb` is found to be `595:103`. The age of the rock is (Mean life of `""_(92)^(238)U` is `T_(0)` ) :

A

`T_(0)` In 1.2

B

`T_(0)` In `(698)/(595)`

C

`T_(0) ("In" 1.2)/("In2")`

D

`T_(0) ("In" (698)/(595))/(In 2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda = (2.303)/(t) log "" (N_(0))/(N)`. From the mass ratio, 103 for Pb is equivalent to 119 of U.
`(1)/(T_(0)) = (1)/(t) 1n ((595 + 119)/(595)) t = T_(0) 1n((714)/(595))`
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