Which of the following orders are incorrect?

Options

A. `H_3 PO_4 gt H_3 PO_3 gt H_3 PO_2` (reducing character)
B. ` SbH_3 gt NH_3 gt AsH_3 gt PH_3` (reducing character)
C. `NH_3 gt PH_3 gt ASH_3 gt SbH_3 ` (basicity)
D. `N_2O lt NO lt N_2 O_3 lt N_2 O_5` ( oxidation state of nitrogen atom)

Answer

A, B

Explanation

As number of reducing hydrogen increases, the reducing character also increases. In `H_3 PO_4` there is no reducing hydrogen so it should be least reducing. As down the group bond energy decreases, the removal of Il becomes easier. Down the group availability of lone pair of electrons decreases as they are present in more concentrated s-orbital.
`1 +1 lt +2 +3 lt +5`