The nitrogen containing compound produced in the reaction of `HNO_3` with `P_4 O_(10)`

Options

A. can be prepared by reaction of `P_4` and `HNO_3`
B. is diamagnetic
C. contains N-N bond
D. reacts with Na-metal producing brown gas

Answer

B, D

Explanation

`4HNO_3 +P_4 O_(10) to 4 HPO_3 +2 N_2O_5`
`N_2 O_5` cannot be prepared by action of `HNO_3` on `P_4` but gives `H_3 PO_4`
` P_4 + 10 HNO_3 to 4 H_3 PO_4 + 20 NO_2 + 4 H_ 2O`
` N_2 O_5 ` has 54 electrons (2 `xx` 7+5 `xx` 8) and hence is diamagnetic
` N_2 O_5` does not contain N-N bond.
`N_2 O_5 ` reacts with Na producing `NO_2`
` Na+N_2 O_5 to NaNO_3 +NO_2 `(brown gas)
Thus, option (B) and (D) are correct.