Among the following, the number of compounds that can react with `PCl_5` to give `POCI_3` is
` O_2 , CO_2 , SO_2 , H_2 O , H_2 SO_4 , P_4 O_(10)`

Answer

4

Explanation

`I ) PCl_5 +O_2 to ` No reaction
`(ii) PCl_5 + CO_2 to ` No reaction
`(iii) 6 PCl_5 + P_4 O_(10) to 10 POCl_3`
(iv) With limited amount of `H_2 O, PCl_5 `gives `POCI_3` but with excess of water it does not give `POCI_3` but gives `H_3 PO_4`
`a . PCl_5 + H_2 O ("limited ") to POCl_3 + 2 HCl`
` b. PCl_5 + 4H_2 O ( " excess") to H_3 PO_4 + 5HCl `
` C. PCl_5 +SO_2 to underset("(thionylchloride)")(SOCl_2 ) + POCl_3`
vi)` 2 PCl_5 + H_2 SO_4 to underset("(Sulphuryl chloride)")(SO_2Cl_2) + 2 POCl_3 + 2 HCl`