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A salt (A) when heated with K2 Cr2 O7 an...

A salt (A) when heated with `K_2 Cr_2 O_7` and conc. `H_2 SO_4` liberates a gas which is absorbed in NaOH solution. The NaOll solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate (B) is formed. The acid radical present in the salt is

A

`NO_(3)^(-)`

B

`Cl^(-)`

C

`S^(2-)`

D

`I^(-)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Cl^(-)`
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A salt (A) when heated with K_2 Cr_2 O_7 and conc. H_2 SO_4 liberates a gas which is absorbed in NaOH solution. The NaOll solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate (B) is formed. (A) is mixed with MnO_2 and heated with conc. H_2 SO_4 when a gas (C) is evolved which tums starch-iodide paper blue. The compound formed, which turns NaOH solution yellow, is:

A salt (A) when heated with K_2 Cr_2 O_7 and conc. H_2 SO_4 liberates a gas which is absorbed in NaOH solution. The NaOll solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate (B) is formed. (A) is mixed with MnO_2 and heated with conc. H_2 SO_4 when a gas (C) is evolved which tums starch-iodide paper blue. What is the colour of gas which is evolved when salt (A) is heated with MnO_2 and H_2 SO_4 ?

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