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Statement-1 : [Ni(CO)4] has square plana...

Statement-1 : `[Ni(CO)_4]` has square planar geometry while `[Ni(CN)_4]^(4-)`has tetrahedral geometry.
Statement-2 : Geometry of above complexes depends upon the nature of ligands attached.

A

Statement 1 is True, Statement 2 is True, Statement 2 is Correct explanation for Statement 1.

B

Statement 1 is True, Statement 2 is True, Statement 2 is NOT a correct explanation for Statement 1.

C

Statement 1 is True, Statement 2 is False.

D

Statement 1 is False, Statement 2 is True.

Text Solution

Verified by Experts

The correct Answer is:
D
`Ni(CO)_4` has tettrahedral geometry and `[Ni(CN)_4]^(4-)` has square planar geometry. `[Ni(CO)_4]` possesses `sp^3` hybridization whereas `[Ni(CN)_4]^(4-)` has `dsp^2` hybridization to show square planar geometry.
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