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This energy lies in visible region and i...



This energy lies in visible region and ie, why electronic transition `t_(2g) hArr e_(g)` are responsible for colour. Such transitions are not possible `d^0 and d^10` configuration.
`Ti_((aq.))^(3+)` is purple while`Ti_((aq.))^(4+)` is colourless because :

A

There is no crystal field effect in `Ti_(4+)`

B

The energy difference between `t_(2g) and e_(g)` of `Ti^(4+)` is quite high and does not fall in the visible region.

C

`Ti^(4+) " had " d^0` configuration

D

`Ti^(4+)` is very small in comparison to `Ti^(3+)` and hence does not absorb any radiation.

Text Solution

Verified by Experts

The correct Answer is:
C
Due to `d^0` configration of `Ti^(4+)` d- d transition is not possible.
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