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The Delta0 for [CoCl6]^(4-) is 18000 cm^...


The `Delta_0` for `[CoCl_6]^(4-)` is `18000 cm^(-1)`. The `Delta_t` for `[CoCl_4]^(2-)` will be

A

`18000 cm^(-1)`

B

`16000 cm^(-1)`

C

`8000 cm^(-1)`

D

`2000 cm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

`Delta_t = 4/9 xx Delta_0= 4/9 xx 18000 = 8000 cm^(-1)`
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