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CH3CH2CH2Brunderset(tBuOH)overset(KOH)to...


`CH_3CH_2CH_2Brunderset(tBuOH)overset(KOH)toB`, product B is

A

`CH_3CH = CH_2`

B

`CH_3CH_2CH_2OH`

C

`CH_3 -underset(OH)underset(|)(CH)-CH_3`

D

`CH_3 -underset(OtBu)underset(|)(CH)-CH_3`

Text Solution

Verified by Experts

The correct Answer is:
A
Strong stercially hindered base gives elimination products.
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