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If |z(1)|= |z(2)| and arg (z(1))+ " arg"...

If `|z_(1)|= |z_(2)|` and arg `(z_(1))+ " arg" (z_(2))= pi//2`, then

A

`z_(1)z_(2)` is purely real

B

`z_(1)z_(2)` is purely imaginary

C

`(z_(1) + z_(2))^(2)` is purely real

D

arg `(z_(1)^(-1)) + "arg" (z_(2)^(-1)) = (pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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